10x^2+9x-162=0

Solution for 10x^2+9x-162=0 equation:

10x^2+9x-162=0

a = 10; b = 9; c = -162;
Δ = b2-4ac
Δ = 92-4·10·(-162)
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6561}=81$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-81}{2*10}=\frac{-90}{20}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+81}{2*10}=\frac{72}{20}
=3+3/5
$